Page 35 - Mathematics_Form_Two
P. 35
Congruence
Figure 2.5 shows that, Consider triangles ABC and XZY in
BA = QP (given) Figure 2.6,
ˆ
ˆ
ABC = PQR (given) BAC = ZXY (given)
ˆ
ˆ
ˆ
ˆ
BCA = QRP (given) AC = XY (given)
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Thus, the two triangles satisfy the AAS ACB XYZ (given)
ˆ
ˆ
=
postulate.
Therefore ∆ABC ≅ ∆XYZ (by ASA
Therefore, ABC PQR (by AAS). postulate).
Since the two triangles are congruent, it Mathematics for Secondary Schools
follows that, all corresponding sides and Example 2�8
angles are equal. That is, In the following figure, prove that
ˆ
ˆ
BA = QP, AC = PR, and BAC = QPR.
ABC CDA.
Similarly, if two angles and one included
side of the first triangle are equal to two
angles and an included side of the second
triangle, then the triangles are congruent
by Angle-Side-Angle (ASA) postulate as
described in Figure 2.6.
Solution
Given a parallelogram ABCD where
AC, is its diagonal.
Required to prove that,
ABC CDA.
Proof: In ABC and CDA it follows
that,
ˆ
ˆ
CAB = ACD .
(alternate interior angles as AB / /DC ).
Similarly,
ˆ
ˆ
ACB = CAD
(alternate interior angles as AD / /BC ).
AC AC= is a common side.
Therefore, ABC CDA (by AAS).
Figure 2�6: Triangles satsfying ASA postulate
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