Page 148 - Mathematics

(b) The -intercepty is obtained when x = 0. Substituting x = into the obtained
0
equation of the line gives,
3 11
y = (0) +
4 4

11
=
4

Thus, the point 0, 11  is the y-intercept.

 4 
The x-intercept is obtained by setting y = 0. Substitute y = into the
0
Tanzania Institute of Education
equation of the line to obtain:
3 11
0 = x +
4 4

3x = − 11

11
x = −
3
 11 
Thus, the point − ,0 is the x-intercept.


 3 



Therefore, the x and y-intercepts are − 11 ,0 and 0, 11  , respectively.



 3   4 

Example 6.18
1
An equation of a line has a gradient of − . If one of the points satisfying the
5
equation is (2, 1), find its equation in the form ax by c+ += 0.

Solution
Mathematics Form One Given m = y –1= – ( ( mx x− and ( ,xy 1 ) (2, 1).= It implies that,
The equation of the line is given by
=
y y−
)
1
1
1
−
1
5
1
x – 2)
5

142

25/10/2024 09:51:56
Mathematics form 1.indd 142 25/10/2024 09:51:56
Mathematics form 1.indd 142