Page 152 - Mathematics
P. 152
Exercise 6.5
1. Find the equation of the line using the given point and gradient:
3
(a) (2, 1), gradient 2 (d) ( 2,− − 4), gradient
2
2
(b) (0, 5), gradient − (e) (0, 0), gradient − 3
(c) (1, − 3), gradient 3
2. Find the equation of the line using the given information:
(a) y-intercept = (0, 2), gradient = 1
(b) -intercepty = (0, 16), gradient− = 4
Tanzania Institute of Education
3
(c) -intercepty = (0, 7), gradient =
4
(d) y (f) y
(0, 2), gradient=-1
(-4, 4)
x
0
x
0
(1, -3)
y
(e) (2, 6) (g) y
(-2, 2) (4, 2)
(0, 3) x
0
x
0
Mathematics Form One 3. In each of the following conditions, find the equation of the straight line in
the indicated form:
mx +
. c
(a) Passing through the point (3, 5) with gradient 2 in the form y =
(b) passing through the point (4, 7) having a gradient of 3,− in the form
0
+=
ax by c+
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Mathematics form 1.indd 146
Mathematics form 1.indd 146 25/10/2024 09:51:58