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Sequences and series


                                                                                   2
               11.  The  first  term  of  a  geometric  Therefore,   S     =    G     +  G     r +  G      r     + ···
                                                                  n    1   1     1
                                                                          n−1
                    progression is 5, and the common                 +  G      r            (1)
                                                                        1
                                       th
                    ratio is 3. Find the 8  term.     Multiply both sides of equation (1) by
               12.  The third term of a geometric  r to get,
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                    progression is 16 and the sixth
                                                                            3
                                                        r  S     =  G     r +  G      r     +  G      r     + ··· +  G      r      (2)
                                                                     2
                                                                                       n
                                                                          1
                                                                   1
                                                             1
                                                        n
                                                                                    1
                    term is 128. Find the common
                    ratio and the first term.
                                                      Subtract equation (2) from equation (1)
               13.  The  first  term  of  a  geometric  to obtain,
                    progression is x, and the common
                                                      S − rS  = G  − G  r n             (3)
                                           th
                    ratio is y. Express the n  term in   n  n    1    1
                    terms of x, y, and n.             Factorization of S  and G  from equation
                                                                      n
                                                                             1
               14.  A geometric progression has a first   (3) gives,
                    term of 2 and a common ratio of    S     (1 − r )   =   G     (1 −  r     ) .
                                                                           n
                                                                    1
                                                       n
                    1
                    3   . Find the smallest value of n for   Make S the subject to obtain,
                    which the n  term is less than 0.01.     n
                              th
                                                              G     (1 −  r     )
                                                                   n
                                                             1 _
               15.  If the sum of the first three terms    S      =      1 − r           (4)
                                                       n
                    of a geometric progression is 21
                                                                                   | |
                                                      where r is a fraction such that   r    < 1.
                    and their product is 216, find the
                    possible values of the first term  Also, subtracting equation (1) from
                    and the common ratio.             equation (2) gives,
               16.  Find the general term of a GP   r  S     −  S      =   G      r     −  G         (5)
                                                                     n
                                                        n   n      1  1  n  1
                    whose seventh term is 13 and tenth
      Mathematics for Secondary Schools  Sum of the first n terms of a geometric   Divide both sides by  r − 1  to obtain,  (6)
                                                      Factorize equation (5) to get,
                    term is 104.
                                                         S     (r − 1 )   =   G     (  r     − 1)
                                                        n

                                                                n
                                                              G     (  r     − 1)
                                                             1 _
                                                          S      =
                                                                         for     r    > 1

              progression
                                                                          | |
                                                               r − 1
                                                       n
              Let the sum of the first  n  terms of a
                                                      Therefore, given a geometric progression
              geometric progression be denoted by
              S     . That is,   S     =  G     +  G     +  G     + ··· +  G     .
                                                                          1
                               1
               n
                                                      ratio r, the sum of the first n terms is
              Since it is a geometric progression, then
                                                                      G     (1 −  r     )
                                                                             n
              G =  G  ,G = n Gr ,G = 2 Gr 2 3  , ,  n  with the first term   G     and the common
                                                                                   , for    r    < 1
                                                                     _
                                                                       1

                                                      given by   S      =
                             1
                                      1
                                 3
                1
                        2
                     1
                                                                n       1 − r       | |
              G =  Gr  n− 1 .                                   G     (  r     − 1)
                                                                   n
                n
                     1
                                                                1

                                                      or   S      =     _     , for    r    > 1.
                                                                             | |
                                                          n      r − 1
                                                   100                 Student\s Book Form Three
                                                                                          18/09/2025   09:59:25
     MATHEMATIC F3 SB.indd   100                                                          18/09/2025   09:59:25
     MATHEMATIC F3 SB.indd   100
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