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Sequences and series


               (b) Given   G     = 24,   r = 5,   n = 10.   2.  Find the sum of the first twenty terms
                           1
                                  n
                                G     (  r     − 1)       of the geometric series  4 + 8 + 16 +  ···

                   From   S      =      1 _     ,
                          n      r − 1
                   substitution of the values into the   3.  Find the sum of the first ten terms of
                                                          the geometric series  2 − 6 + 18 − 54 +  ···
                   formula gives,
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                             24(  5      − 1)          4.  If the sum of the first n   terms of
                                  10

                            S       =     __________
                        10      5 − 1                     a geometric progression with the
                            24 × 9765624                                                  1 __
                           ____________
                              =                           first term 1 and the common ratio
                                  4                          31                           2
                                                             ___
                              = 58593744                  is          , find the number of terms.
                                                             16
                   Therefore, the sum of the first 10   5.  If the  n  term of a geometric
                                                                  th
                   terms is 58,593,744.                   progression is 2 , find the sum of
                                                                         n
                                   n
                                G     (  r     − 1)

               (c) From   S      =      1 _     , it implies   the first five terms.

                          n        r     − 1
                   that        n                       6.  If the sum of the first n terms of a
                          24(  5     − 1)
                     S    =    _________                                n

                      n      5 − 1                        sequence is  3  − 1,  show that the
                              = 6(  5     − 1)            sequence is a geometric progression.
                              n
                   Therefore, the formula for the sum   7.  Find the sum of the first n terms
                   of the first n terms of the sequence   of each of the following geometric
                   is   S      =  6(  5     − 1 ) .       series:
                              n
                      n
               (d) For   S      >  90000 , it follows that  (a)   10  +  50  +  250   +  · · ·
                        n
                      n
                   6(  5     − 1 )   >  90000             (b)   1  −  2  +  4   −  · · ·


                    n
                     5     − 1  >  15000                      1 __  1 __  1 __
                    n
                                                                       8

                     5      >  15001                      (c)            +           +            +  · · ·
                                                              2
                                                                   4
                  Apply logarithm both sides to obtain,  8.  The sum of the first 5 terms of a GP
                                                                     1 ___
                                                                          1 __
                                                                              1 __
                                                               1 ___
                                                          (d)            −           +            −            + · · ·
      Mathematics for Secondary Schools  ⇒>  5.9747   9.  The sum of the first  n  terms of a
                                                                    27
                                                                              3
                                                              81
                                                                          9
                           log 15001
                       n
                  log 5 >
                     n
                       log 5 log 15001>
                  ⇒
                                                          is 124 and the sum of the first 10
                         log 15001
                                                          terms is 4,092. Find the common
                     n
                           log 5
                                                          ratio.
                     n
                  ⇒>
                                                                                         )
                                                                                        n
                                                                                     −
                                                          geometric progression is  ( 51 2 .S =
                   Therefore, the smallest value of n
                                                                               n
                   is 6.
                                                          Find the first term and the common
                                                          ratio.
               Exercise 4.7
                                                          progression 2, 2.2, 2.42, 2.662, . . .
               1.  Given the geometric series         10. How many terms in the geometric
                   2  +  6  +  18  + · · ·   Find the sum of   will be needed so that the sum of
                   the first eight terms.                 the first n terms is greater than 2?
                                                   102                 Student\s Book Form Three
                                                                                          18/09/2025   09:59:26
     MATHEMATIC F3 SB.indd   102
     MATHEMATIC F3 SB.indd   102                                                          18/09/2025   09:59:26
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