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Trigonometry


                                                        It follows that,
             Solution
            Consider the following figure.




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                                                        Therefore, PQ 10.14 m.=


                                                       Example 8�23

                                                       A mobile  phone mast  is erected  on a        Mathematics for Secondary Schools
                                                       hilltop.   The  angle  of elevation  of the
                                                       base  of  the  mast  from  a  point  on  the
                                                       ground 200 m from the base of the hill
                                                       is 35°, while the angle of elevation from

            Let AB be the height of the flag post. It   the same point to the  top of the mast is

                                                        42 .°  Find the height of the mast.
            implies that
                                                       Solution
                  AB
                       =  tan 45° = 1                  The given information is translated into
                 24m                                   the following figure.


                  AB 24m 1=  ×                                B

                                  =  24m
            By using the triangle AQB, it follows             D

            that

                 AB  =  tan 60° =  3                          C         200 m 42º  35º  A
                      QB                               In  ABC,∆   it implies that,
                 QB  =  3                                               BC
                 AB
                        = 3
            Thus,  24m  3                                    tan 42° =  200m
                    QB
                                                                    BC =  200tan 42 m°
                         24m                                         = 180.08 m
                   QB =
                           3                           In  ADC,∆   it implies that,

                                                                        DC
                                                              tan35° =
                                                                       200m
                                                     DB BC DC=        DC =  200tan35 m°
                                                               −

                = 8 3m                                               = 140.04 m


                                                   187
           Student's Book Form Two


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