Page 49 - Mathematics_Std_4

Example 2

12 ) 573

Solution Steps
FOR ONLINE READING ONLY
12 ) 573 1. Divide 5 by 12, it is not sufficient.

47 remainder9 Take 57 then divide by 12 to get 4
and remainder 9.
2. Write 4 below 7, then combine the

remainder 9 and 3 ones to form 93.
3. Divide 93 by 12 to get 7 and
remainder 9. Write 7 below 3 and 9
as the remainder to the right of 47.

Therefore, the answer is 47 and the remainder is 9.

Example 3

23 )14262

Solution
23 )14262

620 remainder 2

Therefore, the answer is 620 and the remainder is 2.

Exercise 3

1. ) 3 457 2. ) 5 99 3. ) 9 68

4. 22 ) 938 5. 12 ) 4005 6. ÷ 644 =10

7. 610 ) 313252 8. 43 ) 267 9. 111 )2 61
4
10. 58 ) 4940 11. ÷ 847 =84 12. 340 )1720

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06/11/2024 17:17:06
MATHEMATICS STD 4 PB 2024.indd 42
MATHEMATICS STD 4 PB 2024.indd 42 06/11/2024 17:17:06