Page 90 - Mathematics_F1

Example 5.16 Add 5 on both sides,

55 7 5= +
5
Find the solution of x += 8. 3y −+
Solution 3y = 12
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5
Given x += 8. Divide by 3 on both sides, Tanzania Institute of Education
Collect the like terms by subtracting 3 y = 12
5 from both sides. That is, 3 y = 4 3

55 =
x +− 85− 4.
Therefore, y =
= 3
Therefore, x =
3
Example 5.19

Example 5.17 Solve for the value of x in the equation
3x
3 12.
Find the value of x that satisfies the 2 +=
8162 .x−
equation x −= Solution
Solution Given 3x +=
3 12.
2
8162 .x−
Given, x −= Subtract 3 from both sides,
Collect the like terms, 3x
3 3 12 3
x + 2x = 16 + 8 2 +− = −

3x = 24 3x = 9
2
Divide by 3 on both sides, Multiply both sides of the equation

24 by 2 to get,
x =
3 3x
92
2
= 8 2 ×= ×
Therefore, x = 8. 3x = 18
Divide by 3 on both sides,

Example 5.18 x = 18
3
Find the value of y if 3y −= = 6 Mathematics Form One
57
Solution Therefore, x = .
6
5 7.
Given, 3y −=

83

25/09/2025 15:01:05
Mathematics form 1.indd 83 25/09/2025 15:01:05
Mathematics form 1.indd 83