Page 91 - Mathematics_F1

Example 5.20 Example 5.22

Solve for the value of z if
5 (3z − 2) 10.= Find the values of x if x = 4.
3 Solution
Solution Given, x = 4.
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5
Given, (3z − 2) 10.= Apply the definition of absolute
3
Multiply by 3 on both sides, value, ± x = 4

5
3× (3z − 2) = 3 10× Either, x+ = 4 or − = 4
x
3
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5(3z − 2) 30= Therefore, x = 4 or x = − 4.
Open the brackets,
15z − 10 = 30 Example 5.23
15z = 40 Solve for the value of x if 6 x− = 1.
Divide by 15 on both sides, Solution
40
z = Given, 6 x− = 1.
15
8 Apply the definition of absolute
= value, ( 6 x± − ) 1=
3
8 Either,
Therefore, z = .
3 + ( 6 x− ) 1 or= − ( 6 x− ) 1.=
1
6 x− = 1 or − 6 x+ =
Example 5.21 x= 5 or x = 7
7
8 Therefore, x= 5 or x = .
Solve for the value of y, if = 2.
3y − 2
Solution

Given, = 2. Example 5.24
3y − 2
Multiply by (3y − 2) on both sides, Solve for the value of x if
2 and represent the
x +
2 =
8 2) × (3y − 2) = 8 2(3y= 2(3y − − 2) solution on a number line.
(3y −
Mathematics Form One 86y= 2 6 − 4 Solution ( x + 2 = ) 2 = 2. Apply the 2.

2)

Given, x +
6y
12 =

definition of absolute value,
12

y =
±
2

=
2.
Therefore, y =
84 Either ( x+ + ) 2 = 2 or − ( x + ) 2 =
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Mathematics form 1.indd 84 25/09/2025 15:01:07
Mathematics form 1.indd 84