Page 117 - Mathematics_Form_Two

Exponents and radicals

2 3 + 2 3 + 2 5 + Solution
(d) = ´ Multiply both the numerator and
2 5 - 2 5 - 2 5 +
( 2 3 + )( 2 5 + ) denominator by 3= + 2 to obtain;

=
( 2 5 - )( 2 5 + ) 1 = 1 × 3 + 2
3 − 2 3 − 2 3 + 2
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+
2 2 2 5 + 6 + 15
= = 3 + 2
-
25
+
2 2 2 5 + 6 + 15 Since 3 1.7321= and 2 1.1442,= it
=
- 3 follows that Mathematics for Secondary Schools
Therefore, 1 = 1.7321 1.4142+
2 + 3 = 2 2 2 5+ + 6 + 15 . 3 − 2

2 − 5 − 3 = 3.1463

6 Exercise 5�11
(e) Given . The rationalizing
72− 1. Rationalize the denominator in each
factor is 7 2.+ Thus, Multiply of the following expressions:
both the numerator and the 1 3
denominator by 7 2.+ to obtain, (a) 5 (b) 18
6 = 6 × 72+

72 72 7 2 (c) 5+ 1 10 (d) 1+ 2
+
−
−
6 ( 72+ ) 2
= 8 3 + 2
−
74 (e) 2 − 3 (f) 3 − 2
6 ( 72+ )
=
3 (g) 9 3 − 2 (h) 27

= 2 ( 72+ ) 5 3 2+ 10 − 7

= 27 4+ (i) x − 2y
x + y
6
Therefore, = = 2 7 +4.
7−2 2. Express each of the following in the
simplest form.

Example 5�37 5− 7
(a)

Given that 3 1.7321= and 3+ 7
1 1
2 1.1442.= Evaluate . (b)
+
3 − 2 3 4 5

111
Student's Book Form Two

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MATHEMATIC F2 v5.indd 111