Page 81 - Mathematics_Form_Two

Algebra

2
(h) 2x + 7x+ 30=
2
Area = 45 m 2 (6 + x) m (i) x − 6x+ 90=
2
(j) x + 5x+ 60=
2
(8 – x) m 2. (a) 2x − 7x+ 30=
FOR ONLINE READING ONLY
2
Area of the new rectangular garden is (b) 3x + 8x+ 50=
(8 – x) (6 + x) = 45. It implies that (c) x − 4x=
0
2
2
0
(8 x - )(6 x + ) = 45 (d) 2x + 6x= Mathematics for Secondary Schools
2
48 8x - 6xx = 45 (e) x − 7x=
+
-
2
0
x 2 2x - - 30 (f) x + 4x+ 40=
=
2
2
x - 3xx - =
30
+
2
+
( xx - 3) 1(x - 3) = 0 (g) 4x − 90=
(x 3)(x - + 1) = 0 (h) 9x − 25 0=
2
2
1 0. 0.
3 0 or x 3
either, x either, - = or x - = 0 or += 1+= (i) ( x − ) 2 = 0
Either x
2
9
1.
Therefore, x = or x = − . (j) 4x − 12x+ = 0
3
2
(k) 3x − 8x+ 50=
But length cannot be negative.
1.
Hence, x = − is rejected. 3. (a) 4x − 2 49 0=
Thus, x = metres. (b) 9y − 6y +=
3
2
10
Therefore, 3 metres should be added to 2
the shorter side. (c) y − 40=
(d) a − 2 8a + 16 0=
Exercise 4�6
2
(e) 25a −=
9 0
Solve the following quadratic equations (f) 2
by factorization method. 9x + 12x + 4 0=
2
(g) 16b = 49
2
1. (a) − x + 4x − 30=
2
(b) (2x+ ) 3 = 0 (h) 4d − 2 20d + 25 0=
(i) x = 1
2
(c) 3x +− 2 12x − 9= 0
2
0
2
(d) x − 16= (j) x = 10x − 25
(e) x = 2 − 2x − 1 (k) (x − ) 3 − 2 25 = 0
2
(f) ( x+ ) 4 = 0 (l) x 2 = 4
2
(g) x − 5x+ 60= 4
75
Student's Book Form Two
11/10/2024 20:12:00
MATHEMATIC F2 v5.indd 75 11/10/2024 20:12:00
MATHEMATIC F2 v5.indd 75