Page 212 - Physics_Form_2
P. 212

Physics for Secondary Schools


            front of the lens. Determine the focal           Exercise 5.4
            length  and  the  magnification  of  the    1.  (a)   Draw ray diagrams to show the
            lens.
                                                               nature and position of images

             Solution                                          formed by a convex lens with
                                                               focal legth of 30 cm for the
          FOR ONLINE READING ONLY
             Given                                             following object distances:
              h =  0  10 cm, v =  7.5 cm, u =  30 cm            (i)  15 cm

                                                                (ii)  30 cm
                                    1   1   1
             Using the lens formula   =    +                    (iii)  45 cm.
                                    f   u   v
                                                           (b)  Use the lens formula to
                                                               determine  the nature and
                  uv    30 cm 
                                ( 7.5 cm)
              f                         10 cm              position of the image formed
                 v   u  ( 7.5 cm)    30 cm
                                                               by the objects in (a).
              f  10 cm (Negative sign indicates       2.  A vertical object 10 cm high, is

             that f is measured against the incident       placed 30 cm in front of a diverging
             ray)                                          lens. An image of an object is formed

                  v                                      7.5 cm in front of the lens. Determine
                       ( 7.5 cm)
             m                   0.25
                  u     30 cm                              the focal length of the lens by using
                                                           a ray diagram.
             The  positive  value  of  magnification    3.  An object 2 cm high is placed 9 cm
             indicates  that the image is erect or         from a convex lens of focal length
             upright. Therefore, the focal length, f       6 cm. Determine the magnification,
             is 10 cm and the magnification, m is          position and nature of the formed
             0.25.                                         image.

                                                        4.  A converging lens forms an upright
           Uses of lenses in life                          image that is four times the size

           Lenses  have  different  applications  in       of the object. Given that the focal
           our daily life. Convex or concave lenses        length of the lens is 20 cm, determine
           are used in medical  eyeglasses for             the object distance.
           correcting  long-sightedness and short-      5.  An object is placed 36 cm from a
           sightedness respectively. Convex lenses         converging lens of focal length 24
           are also used in binoculars, cameras,           cm. If a real image which is 4 cm
           telescopes, microscopes and other optical       high is formed, calculate the height
           instruments. On the other hand, concave         of the object.
           lenses are used in flashlights to magnify    6.  A lens of focal length 15 cm forms
           the light produced by a bulb. These lenses      an upright image four times the size
           are also used in pinholes.

             206
                                                                         Student’s Book Form Two



     Physics Form 2 Final.indd   206                                                        25/10/2025   10:28
   207   208   209   210   211   212   213   214   215   216   217