Page 210 - Physics_Form_2
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Physics for Secondary Schools


           Focal length of a convex lens              The image of a distant object is formed at
           The focal length of a converging lens      the focal point of a convex lens. Therefore,
           can be determined experimentally using     the distance between the screen and the
           various methods. Activity 5.15 describes   lens is the focal length of the lens. Note
           one of the methods.                        that,  this  is  not  a  very  accurate  method

                                                      but a quick way of estimating the focal
          FOR ONLINE READING ONLY
                       Activity 5.15                  length of a convex lens.

             Aim:        To estimate the focal length
                         of a converging lens              Example 5.4
                                                       An object  is placed  12 cm from a
             Materials: a converging lens, lens        convex  lens of a focal  length of 18
                         holder, metre rule, plain     cm.  Using  the  lens  formula,  find  the
                         paper (screen)                position of the image.


             Procedure                                 Solution
             1.  Fix the lens on the holder and the    For a convex lens, the value of
                screen on a stand.                     focal  length  is positive.  Therefore,
             2.  Place the screen and the lens on a     f =+ 18 cm  and  u = +12 cm .
                table in such a way that the light      1    1   1
                from a distant object passes through     f  =  u  +  v
                the lens as shown in Figure 5.43.

             3.  Move the screen closer or away         1    1    1
                from the lens until a sharp image of    v    f  u
                the distant object is focused on the        1    1
                screen.                                       
                                                            18 12
                          Lens    Screen
            Rays                                            2 cm 3 cm
            from                                               36 cm
            distant
            object                                             1
                                                          
                                                             36 cm
                          Figure 5.43
                                                        v  36 cm
             4.  Measure the distance between the      Because the value of v is negative, the
                screen and the lens.
                                                       image is virtual (on the same side as

             Question                                  the object) and is 36 cm from the lens.
             What is the distance  between the         Because the image is virtual, it is also
             screen and the lens?                      erect.


             204
                                                                         Student’s Book Form Two



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