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Computer Science  (d) Examples of subnetting

                  Example 3.1:

            Imagine a ZCB group of companies Ltd  have an IP address of 192.168.1.0/24
            according to information from its IT department. The company needs to create
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            four (4) subnets. As an IT Manager, perform this task.
            Step 1: Determine the subnet mask

             (i)   The original default network mask is 255.255.255.0 (/24), which allows for
                  256 IP addresses (2^8).
             (ii)  To create four subnets, you need to borrow 2 bits from the Host ID part.

             (iii)  To calculate the number of subnets, use the formula, number of subnets=2
                                                                                         n
                  , where n is the  borrowed bits. In this case, n=2, therefore 2  = 4 subnets.
                                                                            2
             (iv)  Change the borrowed 2 bits from bit 0 to bit 1 in the host portion (add them
                  to the network ID portion of the mask). This is to say, the default mask for
                  class C 11111111 1111111 11111111 00000000 will now be come 11111111
                  1111111 11111111 11000000
             (v)   The resulting subnet mask is now 255.255.255.192 (/26).

             (vi)   From the remaining zeros of the subnet mask, calculate the number of
                  addresses per each subnet as allowed (2 ,where n is the number of zeros in
                                                        n
                  the host ID part of the subnet mask).
             (vii)  Taking the remaining 6 zeros in the host ID portion of the mask  (2 ), which
                                                                                  6
                  allows for 64 IP addresses per subnet.

            Step 2: Calculate subnet addresses

            Each subnet has 64 address ranges, the granted address will be the first address
            then add 63 to find the last address in each case. Remember the first address is the
            subnet address and the last address is the broadcast address.
             (i)   Subnet 1: 192.168.1.0/26 (Range: 192.168.1.0 - 192.168.1.63)
             (ii)  Subnet 2: 192.168.1.64/26 (Range: 192.168.1.64 - 192.168.1.127)
             (iii)  Subnet 3: 192.168.1.128/26 (Range: 192.168.1.128 - 192.168.1.191)

             (iv)  Subnet 4: 192.168.1.192/26 (Range: 192.168.1.192 - 192.168.1.255)

            Step 3: Assign addresses

            Each subnet can accommodate up to 62 hosts (64 total addresses minus 2 for
            network and broadcast addresses).



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     Computer Science Form 5.indd   160                                                     23/07/2024   12:33
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