Page 214 - Physics
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Physics for Secondary Schools


           The displacement of the object is equal    PE depends on mass, acceleration due to
           to  the  change  in  its  height  as  shown in   gravity and height of an object above a
           Figure 9.15. Thus,
                                                      reference level as opposed to KE which is
                 d = h − h                            dependent on mass and velocity. When a
                       f    i
           Substituting this expression on the right   force lifts an object at a constant velocity,
           side of the above equation gives:          the work done by the  force equals the
                               f (
                       Fd = mg h –  h i)              change in the object’s gravitational
                                                      potential energy. That is,
                                                                               PE = W = mgh.
                 ∴ Fd = mgh − mgh .
                             f      i
           The quantity on the left side of the               Example 9.5
           equation is the work done. The quantities,   A stone of 2 kg mass falls from a height

            mgh and mgh are the respective potential    of  25 m above the ground. Calculate
                i        f
           energy values at the heights h  and h . The   the PE initially possessed by the stone.
                                        i     f
           difference between  mgh and mgh  is          Solution
                                     i         f
           the change in the object’s PE. It follows      m =  2 kg, g =  10 m/s 2
           that, change in potential energy is equal      PE =  mgh
           to work done (W) in lifting the object that
                                                                         2
           is  ΔPE = W.                                   = 2 kg × 10 m/s × 25 m
                                                            500 kgm /s   2  2  500 J
           If  h = 0, that  is the  ground level  is the
               i
           reference level, then                        Therefore,  PE  of the stone is 500 J.
                   PE = mgh
           where h is the height from the surface.           Example 9.6
                      1  1                              A 2 kg object is at rest on a table 1.2 m
                         mgh.
                PE =
           Thus,  PE = mgh.
                      2  2                              above the fl oor. The ceiling in the room
           When determining the PE of an object, a      is 2.8 m above the fl oor as shown in
           reference level from which h is measured     Figure 9.16.
           must be chosen. The choice is arbitrary
           and the reference level can be located                                     Ceiling
           anywhere. For convenience, the reference
           level  h  is considered to have zero  PE.
                  i
           Note that, while the  PE of an object       Table      2 kg                2.8 m
           depends on the location of the reference
           level, the change in PE does not. The SI                          1.2 m
           unit of PE is Joules which is equivalent to                                Floor
           (kgm /s ) just like KE.                                   Figure 9.16
                   2
                2

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                                                                         Student’s Book Form One



     Physics Form 1 Final.indd   208                                                        16/10/2024   20:58
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