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Exponents and radicals


           Example 5�17                                Example 5�19
           Find the value of  n  in each of the        Solve for x and y if   2 ×  x  3 =  y  144.
           following equations:                        Solution

                                         n
           (a)  2 n+1  = 64        (b)  4  = 16        From  2 ×  x  3 =  y  144.
           Solution = 64                               Writing 144 in exponential form gives,
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                 n+1
           (a)  2
     Mathematics for Secondary Schools        2 n+1  = 2 6    It follows that,   2 ×  4  2. 2
                                                                  2
                                                              4
                                                                 3
                                                             2 ×
                                                       144 =
                Express 64 in power form to obtain

                                                                   2 ×
                                                                  3 =
                                                                          3
                                                                   y
                                                               x
                Comparing exponents gives,
                                                       Comparing exponents of the same base
                     n + 1 = 6



                           n = 5
                                                       gives  x =
                                                                4 and y =
                Therefore, n = 5.
                 n
           (b)  4  = 16                                Therefore, x = 4 and y = 2
                Express in power form and compare      Example 5�20
                exponents to obtain                            x   y       x   y− 1
                 n
                      2
                4  = 4                                 Given  4 =  2  and 3 = 9   ,  find the
                   n = 2                               value of x and y.
                Therefore,  n = 2.                     Solution
                                                       Simplify  4 =  2  to get
                                                                 x
                                                                      y
           Example 5�18                                2 =  2. Comparing the exponents gives
                                                              y
                                                        2x
           Find the value of b in each of the following  ⇒  2x =  y                           (i)
           equations:                                  3 =  9 y−  1  =  3 = 3 2 y−  2
                                                        x
                                                                   x
                                          3
           (a)  b  = 27       (b)  (b + 1)  = 64  9 y−  1  =        3=  2 y−  2
                 3
                                              x
                                                       3
                                                        x
                                             3 =
           Solution                                     Comparing exponents of the same base,
                 3
           (a)   b  = 27                               gives
                                                                 2
                Express 27 in power form to obtain,       x =  2y −                          (ii)
                      3
                b  = 3                                 Solving equations (i) and (ii)
                 3
                b = 3                                  simultaneously gives
                Therefore, b = 3.                      x =  2   and  y =  4 .
                        3
           (b)   (b + 1)  = 64                             3          3
                Write 64 in power form to get
                        3
                            3
                 (b + 1)  = 4                          Example 5�21
                      b + 1 = 4                        Solve for  x in each of the following
                            b = 4 – 1                  equations
                       b = 3                           (a)  5 +  x  5 (x− 1)  =  30.
                Therefore, b = 3.                      (b)  4  + 2  – 20 = 0
                                                            x
                                                                 x
                                                    98
                                                                            Student's Book Form Two
                                                                                          11/10/2024   20:12:21
     MATHEMATIC F2 v5.indd   98
     MATHEMATIC F2 v5.indd   98                                                           11/10/2024   20:12:21
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