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Exponents and radicals



                        1                                   1              1
                         ⇒  5 =  3  3  5                  8     3  =     2 2 2     3
                                                                   × ×
                     4   1  4  1 4 × 4                27      3 3 3   1
                     5    =  5                            1   æ    3 ö  3
                                                                   2ö
                                                     æ  8  3  = ç  æö  ÷  =  2
                          =  5                         ç  27 ø ÷  ç  ç÷  ÷  3
                                                                   3
                                                                 èø
                                                       è
                                                                è
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                        1 4 5  4  1 5                    Therefore,   æ  ç  8  ø  ÷  1 3  =  2 ö   .
     Mathematics for Secondary Schools                 5 5       5 =  1 5 = 5 5 5 × 5 5  Example 5�24 27 ø  3  1 3   ) �
                   ⇒
                       5 =
                   
                      1
                                                                   è
                   
                   
                          =
                            5
                    ⇒
                                                       Find the value of ( 125-
           Based on the previous results, it can be
                                                       Express –125 as a product of prime
           concluded that if x is a positive number    Solution
           and n is any positive real number, then     factors.
                                                                    –125 = (–5) × (–5) × (–5)
              n   1  n  1        1 n  n                        ( 125-  ) ( ( ) ) 1 3  =  ( ) 5-  3  ´  1  3 = -  = -    5
                                                                    1
                                                                             3
                                                                           5
              x    =  x = x and  x =    . x                       3
                                                       1          1         1
                                                                  3
                                                                5
                                                  ( 125-  ) ( ( ) ) 3  =  ( ) 5-  3  ´ 3 = -  = -    5
                                                         3
                                               1
                                                                               1
                        1                     ) (  ( ) )  1       3  ´
                                                        3
                                                                    3 = -
                                                             ( ) 5-
                                                           =
                                                          3
            Generally,  x =  n  , x for  x > 0.  ( 125-  3  5                         = -    5
                        n
                                                                          1
                                                        Therefore, ( 125-  ) = - 5.
                                                                          3
           Example 5�22
                               1                        Exercise 5�6
           Find the value of  49 .
                               2
           Solution                                     Simplify each of the following
           Express 49 as a product of prime factors.    exponential numbers:
                                                               1
            49 7 7 7= ´ =  2                            1.  (64)
                                                               2
                    1       1    2´ 1                            1
                                                                 3
                          2
           Thus, 49 =  ( ) =   7  2  = 7 1              2.  (1000)
                        7
                    2
                            2
                        1                                        1
           Therefore,  49 = 7.                             æ  81 ö  2
                         2
                                                        3.   ç  ÷
           Example 5�23                                    è  625 ø
                                                                 1
                                                                 2
                           1                            4.  (0.25)
                     æ  8 ö  3
           Simplify   ç   ÷    �
                     è  27 ø                                      1 3
           Solution                                     5.  (0.027)
           Express the base in power form and                  1
                                                               4
           simplify.                                    6.  (81)
                                                   100
                                                                            Student's Book Form Two
                                                                                          11/10/2024   20:12:24
     MATHEMATIC F2 v5.indd   100                                                          11/10/2024   20:12:24
     MATHEMATIC F2 v5.indd   100
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