Page 102 - Mathematics_Form_Two
P. 102

Exponents and radicals


                  ab      a 4  b 17                                 2  3    45       0
                    4 17
              (b)       =     ´                        (c)     ( 2a b c−  2 −  ) ( 3ab c  )(xyz )
                  ab      a 10  b 11                               2  3
                   10 11
                      a =  4 10 17 11                       =  ( 2ac−  6  )  ×  ( 3ab c  ) 1×
                           b
                             -
                        -
                                                                             4 5
                                                                 b
                        6 6
                        -
                    =  a b                                    − 2 × a × c ×× ×   4  c 5
                                                                3
                                                                        3
                                                                    6
                                                                          3 ab ×
            (b) FOR ONLINE READING ONLY
                      æ  =  ç  è  b ö a 6 6 ÷  ø            =  −×      7  × b b × c 8
                                                                          6
     Mathematics for Secondary Schools  Therefore, b ab  = æö 6 .  = −  2 × × b 2 1 b 6 − 7 2  −  c 7 8  −  8
                                                                           4
                                                               83 a×
                                                            =
                          6
                      æö
                    =
                                                                    1
                                                                 3
                                                                       a ×
                                                                   3
                      ç÷
                                                            = −
                       a
                      èø
                                                                     b
                         ab
                                  b
                          4 17
              Therefore
                                 ç÷
                                                                 3
                          10 11
                                  a
                                                               2 ×
                                                                         a ×
                                                                              c
                                                                    3 ×
                                                                     −
                                                                 −
                                                                                  4 5
                                                                                           0
                                                                             3
                                                                       2 −2
             Example 5�15        èø                    Therefore,  (−2a b c) (3ab c )(xyz) =
                                                                             −2
                                                                            b
                                                                  −
             Simplify each of the following                             2 ×3 ×a ×c   −8
                                                                           −1
                                                                                −7
                                                                      −3
             expressions and give your answers in
             negative exponents:                       Example 5�16
             (a)   3 9                                 Find the  reciprocal  of each  of the
                  3 16                                 following and simplify the answers:
                   (0.7 ) 6
             (b)                                       (a)   19      (b)   1       (c)  0.2
                   (0.7 ) 2                                              9              1
                                                                             2
                                                                          ab
                            3
                                  45
             (c)  ( 2a b c−  2 − 2  ) ( 3ab c  )(xyz ) 0  (d)   14 2  (e)  ( ) 4   (f)  7 2
             Solution                                  (g)   (0.25) − 2
                                                       Solution                   1
                                                       (a) The reciprocal of 19 is   .
                                                                            1    19
                                                       (b) The reciprocal of   is 9.
                                                                            9
                                                       (c) The reciprocal of 0.2 is   1  = 10  = 5.
                ( ) 6  = (0.7  ) 62                                           2   0.2  2  1
                0.7
                                                                                   1
                             -
                ( ) 2                                  (d) The reciprocal of 14 =  14 2  =  196  .
                0.7
                       0.7
                     = ( ) 4                           (e) The reciprocal of   1
                                                                      1
                                                                4
                                                            ab
                                                              2
                         1                                 ( ) =           =
                                                                              48
                     =                                              ( )  4   ab
                                                                       2
                                                                     ab
                       ( ) -  4                                              1     2
                       0.7
                      ( )  6     1                     (f)  The reciprocal of  7 2  = 7 =  49 .
                       0.7
            Therefore,      =                          (g) The reciprocal of
                      ( )  2  ( ) -  4                     (0.25) =  (0.25) = 0.0625.
                               0.7
                       0.7
                                                                  2
                                                                 −
                                                                           2
                                                    96
                                                                            Student's Book Form Two
                                                                                          11/10/2024   20:12:20
     MATHEMATIC F2 v5.indd   96                                                           11/10/2024   20:12:20
     MATHEMATIC F2 v5.indd   96
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