Page 102 - Mathematics_F1
P. 102
5x + 2 ) y = 40 (5) 6. 0.7x − 0.5y = 2.5
0.7x + 0.3y = 2.9
5(x + 10 ) y = 120 (6)
2x y+= 0
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Subtract equation (6) from (5): 7. x − 2y = − 5 Tanzania Institute of Education
5x + 2 ) y = 40
− 4 1
5(x+ 10 ) y = 120 x + y = 3
5x – 5x + 2y – (+10y) = 40 – 120 8.
1 + 2 = − 1
2y – 10y = – 80 x y
–8y = – 80 8 12
x − y = − 2
− 8y = − 80 . 9. 5 3
− 8 − 8 x + 2y = 1
Hence, y = 10.
0.2x + 0.3y = 0.1
Therefore, x = 4 and y = 10. 10.
0.3x − 0.1y = 0.7
0.05x + 0.02y = 0.01
Exercise 5.7 11.
0.02x − 0.03y = − 0.11
Solve the following simultaneous
equations by using elimination 1 x + 3y = 3
method. 12. 2
y
2x += 5 3
1. 4 x − 2y = − 2
−=
4x y 7
3pq+ = 6 2v = 1
2. 13. u +
5pq+ = 8 3u − 4v = 8
5x − 2y = 16
3. 2pq+ = 4
x + 2y = 8 14. − 3p + 5q = − 19
8x + 5y = 40
4.
9x − 5y = 5 2m + 1 n = 3 Mathematics Form One
7x − 4y = 17 15. 3
+=
5. − 3mn 6
5x − 4y = 11
95
25/09/2025 15:01:13
Mathematics form 1.indd 95
Mathematics form 1.indd 95 25/09/2025 15:01:13

