Page 160 - Mathematics_Form_Two
P. 160
Sets
n (E ∩ K ) ′ = n (E) n− (E ∩ K)
= 40 – 30 = 10
Therefore, 10 students study English
only.
(b) The number of students who study
FOR ONLINE READING ONLY
Kiswahili only is given by:
(a) Elements of B only = 6 – 4 = 2.
Mathematics for Secondary Schools (b) A ⊂ B. This is because all elements = 60 – 30 = 30
Therefore, B has 4 + 2 = 6 elements.
(K) n−
n
K)
(E ∩
n
(K ∩
E ) ′ =
The number of students who study
in set A are contained in set B.
English or Kiswahili or both are:
Example 7�24
30+30+10 = 70
In a class of 120 students, 40 study
who study neither Kiswahili nor
English, 60 study Kiswahili, and 30 Therefore, the number of students
study both Kiswahili and English. Find English are:
the number of students who study: 120 – 70 = 50 students.
(a) English only. Example 7�25
(b) Neither English nor Kiswahili. In a certain school, 50 students eat
Solution meat, 60 eat fish, and 25 eat both meat
Let = {All students in the school} and fish. Assuming that every student
eats meat or fish, find the total number
E = {All students who study English} of students in the school.
K = {All students who study Kiswahili} Solution
Representation of the three sets in a Let = {All students in the school},
Venn diagram is as follows. M = {All student who eat meat}, and
F = {All students who eat fish}.
The Venn diagram representing these
information is as follows:
Given n(E∩K) = 30, n(E) = 40, and
n(K) = 60. From the Venn diagram, total number
of students = 25 + 25 + 35 = 85.
(a) The number of students who study
English only is given by: Therefore, there are 85 students in the
school.
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Student's Book Form Two
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