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Physics for Secondary Schools


           can hold for a given potential difference is called capacitance, C. If Q is the charge
           stored by a capacitor, then:

                                         Amount of charge stored by acapacitor ,Q
                        Capacitance ,C =
                                           Potential differencebetween plates ,V

                                     C =  Q
          FOR ONLINE READING ONLY
                                          V

                                     Q
           Since Q  , the ratio of    is constant for a given capacitor. Also, Q CV=  .
                      V
                                     V
           The SI unit of capacitance, C, is the farad, F. Normally, the value of C is a very small
           number; therefore, the millifarad (mF), microfarad (μF), nano farad (nF), and picofarad
           (pF) are also used, where:
                   1 mF 10 F;   3   1 μF 10   6  F; 1 nF 10   9  F and 1 pF 10   12  F




                                                                 Q
             A farad is defined as the capacitance           C =
             of a capacitor  when a charge of                    V
             one  coulomb  changes  its potential            Q CV=
             difference by one volt.
                                                        but, C   200 μF 200 10     6  F
                                                                 2 10
           One farad is the capacitance of a very large               4  F
           capacitor. In real-world applications, radio
           receivers usually measure capacitance in      Therefore, Q       4
                                                                       2 10 F 10 V
           microfarads,  while modern electronic                              = 2 10 C   3
           circuits,  such  as  those  found  in  hi-fi
           systems, often measure  capacitance  in                          =  2 mC
           picofarads.                                 Therefore, one plate has a charge of
                                                         2 mC, and the other has + 2 mC.
                Example 1.2
            A capacitor with a capacitance of 200 μF
            is being charged, and the potential             Exercise 1.2
            difference across its plates is 10 V. What   1.  A capacitor with a capacitance of
            is the amount of charge accumulated            50 pF is charged to 30 V. What is
            on its plates?                                 the charge on its plates?

            Solution                                    2.  A parallel-plate capacitor is
            Given, p.d = 10 V,                             connected to a battery and fully
            capacitance = 200 μF                           charged. While still connected to


              22
                                                                         Student’s Book Form Two



     Physics Form 2 Final.indd   22                                                         25/10/2025   10:25
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