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Sequences and series


              in the sequence 1, 2, 3, 4, ..., the next   Example 4.3
              term is 5 since each term increases by   Given the sequence  2,  4,    6,  8, .  .  . ,  find:
              1. In the sequence 2, 1, 4, 3, 6, 5, ..., the   (a) the fifth term.
              pattern alternates between subtracting   (b) the n term.
                                                               th
              1 and adding 3, so the next two terms
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              are 8 and 7.                             Solution
                                                       (a) The difference between two
                                                          consecutive terms is 2. Hence,
               Example 4.1                                every term is obtained by adding
                                                          2 to the previous term. Thus, the
               List down the terms of each sequence
                                                            th
                                                          5  term = 8 + 2  = 10.
               obtained from the following descriptions.  Therefore the fifth term is 10.
                                                                st
               (a) Multiples of 3 which lie between    (b) The 1  term is  2  =  2 × 1
                                                                nd
                   0 and 20.                              The 2  term is  4  =  2 × 2
                                                                rd
               (b) Squares of counting numbers from       The 3  term is  6  =  2 × 3
                                                                th
                   1 to 10.                               The 4  term is  8  =  2 × 4
               (c) Counting numbers less than 50 but                            ⋮      ⋮
                                                                     th
                   divisible by 9.                                The n  term =   2 × n
                                                                      th
               Solution                                Therefore, the n  term is  2 × n   or   2n.
               (a) The terms are 3, 6, 9, 12, 15, 18.
               (b) The terms are 1, 4, 9, 16, 25, 36,   Example 4.4

                   49, 64, 81, 100  .                  Find the next two terms in each of the
               (c) The terms are 9, 18, 27, 36, 45.    following sequences:
                                                       (a)  22,  37,  52,  67,  . . .
      Mathematics for Secondary Schools  Find the fifth term of the sequence    Solution
                                                       (b)  4,  2,  0,  − 2,  . . .
               Example 4.2
                                                                      1
                                                                 1
                                                          1 __ 1 __ ___ ___
                                                       (c)          ,          ,          ,          ,  . . .
                                                          3 6 12 24
               1,  4,    7,  10,  . . .
                                                       (a) In the sequence  22,  37,  52,  67, ...,
                                                          every two consecutive terms differ
               Solution
                                                          by 15.  Thus, the fifth term is
               From the given terms of the sequence,
                                                          67 + 15 = 82, and the sixth term is
               the difference between two consecutive
               terms is 3. Hence, every term is obtained
                                                          Therefore, the next two terms are
               by adding 3 to the previous term. Thus,
                                                          82 and 97.
               the fifth term is  10 + 3 = 13.  Therefore,   82 + 15 = 97.
               the fifth term is 13.                   (b) In the sequence  4, 2, 0, − 2, ...  every
                                                          two consecutive terms differ by  − 2.




                                                    84                 Student\s Book Form Three



                                                                                          18/09/2025   09:59:18
     MATHEMATIC F3 SB.indd   84                                                           18/09/2025   09:59:18
     MATHEMATIC F3 SB.indd   84
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