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Physics for Secondary Schools


           signs of values such as image distance, image height, and focal length. Two
           sign conventions, namely the new Cartesian convention and the real is positive
           convention, are commonly used. The two sign conventions are summarised in
           Table 4.4.

           Table 4.4: Sign conventions
          FOR ONLINE READING ONLY
                 New Cartesian convention                 Real is positive
              1.  All distances are measured from the   1.  All distances are measured from the
                 mirror as the origin                      mirror as the origin
              2.  Distances measured in the opposite   2.  Distances of real objects and images
                 direction of the incident light are       are positive
                 negative
              3.  Distances measured along the         3.  Distances of virtual objects and
                 direction of the incident light are       images are negative
                 positive


           Generally, the sign conventions  for the
           given quantities in the mirror equation and   Solution
           magnification equations are as follows;      Given  h = 4.0 cm  , u = 8.3 cm,
                                                                0
             (a) f is positive if the mirror is concave.    f = 15.2 cm
             (b) f is negative if the mirror is convex.
                                                        Using formula
             (c) v is positive if the image is real and
                located on the same side of the mirror         1  =  1  +  1
                as the object.                                 f   u   v

             (d) v is negative if the image is virtual   Upon rearranging the formula
                and located behind the mirror.
                                                              fu
             (e)  h  is positive if the image is upright   v   u   f
                 i
                and, therefore, virtual.

             (f)  h  is negative if the image is inverted   v  15.2 cm   8.3 cm   18.28 cm
                 i
                and, therefore, real.                        8.3 cm 15.2 cm


                Example 4.5                             From m   h i     v , hence,  h    vh 0
                                                                  h     u           i   u
            A 4.0 cm light bulb is placed 8.3 cm                   0
            from a concave mirror with a focal                
                                                               ( 18.28 cm) 4 cm
            length of 15.2 cm. Determine the image        h   i     8.3 cm          8.81 cm
            distance and the image size.



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                                                                         Student’s Book Form Two



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