Page 159 - Physics_Form_2
P. 159

Nature and reflection of light


            Therefore, the image is formed at a            Example 4.7
            distance of 18.28 cm from the mirror       An electric room heater uses a concave
            with a size of 8.81 cm. The negative       mirror to reflect infrared (IR) radiation
            sign of the image  distance indicates      from a hot coil. Note that IR follows
            that  the image  is formed behind the      the  same  law  of  reflection  as  visible
          FOR ONLINE READING ONLY
            mirror.                                    light. Given that the mirror has a radius
                                                       of curvature of 50 cm and produces an
                                                       image of the coil 3 m away from the
                Example 4.6                            mirror, where is the coil located?
            A 4.0 cm light bulb is placed 35.5 cm      Solution
            from a convex mirror with a focal          Using the new Cartesian convention,
            length of 12.2 cm. Determine the image            R
            distance and the image size.                 f       25 cm, v = 300 cm
                                                              2

            Solution                                    1    1    1
            By the new Cartesian sign conversion;        v   f   u
             u  35.5 cm (Measured against the               fv

             direction of incident light),              u   v   f
              f =+ 12.2 cm                                   300 cm 
                                                                       ( 25 cm)
                                                        u                        27 cm
                    1   1   1                                300 cm ( 25 cm)
               From,   =  +
                    f   u   v                           Therefore, the coil is 27.27 cm in front
                                                        of the mirror.
              1    1    1
              v   f   u                                    Example 4.8

                   fu
              v                                       An object  3 cm high is placed  at a
                  u   f                               point 30 cm from the pole of a concave

                    35.5 cm 12.2 cm                  mirror whose focal  length  is 12 cm.
              v                        9.08 cm       Using  the  mirror  formula,  find  the
                           
                    35.5 cm 12.2 cm
                                                       position, the height and the nature of
                    v    9.08 cm                     the image formed.
              m                  0.26
                   u     35.5 cm                      Solution
                                                        12 cm, f = 30 cm, u =  h  = 3 cm
              h   i  mh   o  0.26   4 cm 1.04 cm                           o
                                                              1  =  1  +  1
            Therefore, the image size is 1.04 cm,             f   u    v
            and the image distance is 9.08 cm                 1   1    1
            behind the mirror.                                v    f    u



                                                                                        153




     Physics Form 2 Final.indd   153                                                        25/10/2025   10:27
   154   155   156   157   158   159   160   161   162   163   164