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Nature and reflection of light

            Derivation                                  5.  Set up a ratio
             3.  Consider the ray diagram setup of
                Figure 4.30                                From ABP    :    A B P
                                                                            11
                (a)  Place an object AB at a distance        AB     B P    h    v
                                                                     1
                                                              11
                     u  from the pole.                       AB     BP    h i    u                   (1)
                (b)  The  image A B  forms at a                             0
          FOR ONLINE READING ONLY
                                  1  1
                    distance  v .                                   DEF :    A B F
                                                                         11
                (c)  The focal length  f is the              AB     B F     h   v   f
                                                                     1
                                                              11
                    distance from P to F (principal          DE     FE    h i    f         (2)
                    focus).                                                  0
                                                       6.  Compare Equations (1) and (2) :


                                   A            D             v    v   f
                                                              u     f
                          B
                            1
                                  C B    F    E  P
                                                              vf   uv uf
                                                              vf    uv    uf
                                                              uv   uv   uv

                          A 1                                 f       f
                                                                  1
                                                              u     v
             Figure 4.30: Geometry of a concave mirror

             4.  Identify similar triangles                   f      1    1       1
                (a)  (Triangle 1): △ABP (object                   v  u 
                    triangle) and  AB P  11   (image         1   1   1
                    triangle) are similar                     v  +  u  =  f


                     (i)    APB   A PB 1  (from    This equation  applies to both concave
                                      1
                         angle of incidence = angle   and convex mirrors with both convention
                         of reflection).              signs.

                     (ii)  Both are right-angled.
                                                      Sign convention for the mirror equation
                (b)  (Triangle 2): △DEF (Mirror-      Recall, the characteristics of images formed
                    focal triangle) and  AB F        by spherical mirrors depend on whether
                                             11
                    (Image-focal triangle) are similar     the mirror is concave or convex. The size,

                     (i)   EFD    B FA 1           position and nature of the  image also
                                                      depend on the position of the object in
                                      1
                         (Vertically opposite angles)  front of the mirror. To determine the image
                     (ii)  Both are right-angled.     properties, there is a need to   indicate the

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     Physics Form 2 Final.indd   151                                                        25/10/2025   10:27
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