Page 130 - Mathematics
P. 130

Example 6.5

               Find the gradient of a straight line given in the following figure.

                                                   y

                                                   6

                                   P(-3, 5)
                                                   5

                                                   4
    Tanzania Institute of Education
                                                   3


                                                   2

                                                      Q(0, 1)
                                                   1



                          -4    -3    -2    -1     0       1     2     3   x

                                                 -1


                                                 -2




               Solution

               Given points P( 3, 5)−   and Q(0, 1).
               Let ( ,xy 1 ) ( 3, 5)= −   and ( ,x y 2 ) (0, 1).=
                                           2
                     1
                          y −  y
               From  m =  x − x 1 1  ,   it follows that,
                           2
                           2
    Mathematics Form One             m =  0 ( 3)− −   4 .
                           15−


                           4
                             = −
                           3
               Therefore, the gradient of a line PQ is  −
                                                      3




                                                 124




                                                                                        25/10/2024   09:51:47
   Mathematics form 1.indd   124
   Mathematics form 1.indd   124                                                        25/10/2024   09:51:47
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