Page 131 - Mathematics_F1
P. 131
Example 6.5
Find the gradient of a straight line given in the following figure.
y
FOR ONLINE READING ONLY
6
P(-3, 5)
5
4
Tanzania Institute of Education
3
2
Q(0, 1)
1
-4 -3 -2 -1 0 1 2 3 x
-1
-2
Solution
Given points P( 3, 5)− and Q(0, 1).
Let ( ,xy 1 ) ( 3, 5)= − and ( ,x y 2 ) (0, 1).=
1
2
y − y
2
From, m = x − x 1 1 , it follows that,
2
Mathematics Form One m = 0 ( 3)− − 4 .
15−
4
= −
3
Therefore, the gradient of a line PQ is −
3
124
25/09/2025 15:01:32
Mathematics form 1.indd 124
Mathematics form 1.indd 124 25/09/2025 15:01:32

