Page 133 - Mathematics_F1
P. 133
y
D(x , y ) E(x , y )
1 1 2 1
y
1
Tanzania Institute of Education
O x x x
2
1 . READING ONLY
Figure 6.3: A horizontal line DE with zero gradient
The gradient of the straight line joining the two points D( , )xy and E( , )xy
1
1
1
2
can be obtained as follows:
FOR ONLINE
y − y
From, m = 2 1
x − x 1
2
But, y = y 1 and x ≠ x 2 . It implies that,
2
1
y − y
m = 1 1
x − x 1
2
0
=
x − x 1
2
= 0
Therefore, the gradient of a horizontal line DE is 0.
Mathematics Form One Since the gradient of the line segment DE is zero, then the line DE is horizontal.
On the other hand, if the line is vertical, the change in x -values is zero which
makes the denominator zero. Consider the line PN in Figure 6.4.
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Mathematics form 1.indd 126
Mathematics form 1.indd 126 25/09/2025 15:01:33
